Derivation of Thin Film Interference
   
  
    
     
       
      
        
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          Consider light incident on a thin slab of glass
         whose index is nag. The slab is
        situated in vacuo.The wave equation yields
        line 1 outside the glass |  
       
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     1 |  
    
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    Inside the glass the wave equation yields line 2. |  
    
     2 | 
    
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    Divide line 1 by line 2 to get line 3. |  
    
     3 | 
    
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     The left hand side of line 3 is the definition of index
    of refraction for glass. |  
    
     4 | 
    
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     Line 5 shows that the wavelength of light is different
    in glass than in vacuo. |  
    
    5 | 
    
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     Two factors contribute to interference--path length
    difference and the Lloyd's mirror effect. We get constructive
    interference if the PLD is one half wavelength and the thickness
    is 1/4 wavelength |  
    
     6 | 
    
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     constructive interference occurs for other thicknesses,
    namely, odd multiples of quarter wavelengths. We generate these
    values as shown |  
    
     7 | 
    
      m = 0, 1, 2... |  
  
  
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     Line 7 shows the wavelength in glass. We need the wavelength
    in vacuo. We substitute from line 5. |  
    
     8 | 
    
      m = 0, 1, 2... |  
  
  
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     Rearranging terms, line 9 describes constructive
    interference |  
    
     9 | 
    
       m = 0, 1, 2... |  
  
  
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     Destructive interference
    comes when the thickness is even multiples of quarter wavelengths |  
    
     10 | 
    
      m = 0, 1, 2... |  
  
  
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      Finally, lines 9 & 10 work when the LMPC applies
    to just one surface of the film. If the LMPC occurs at both surfaces,
    then the equations at lines 9 & 10 are REVERSED |